• KindaABigDyl@programming.dev
    177·
    2 days ago
    typedef struct {
    bool a: 1;
    bool b: 1;
    bool c: 1;
    bool d: 1;
    bool e: 1;
    bool f: 1;
    bool g: 1;
    bool h: 1;
} __attribute__((__packed__)) not_if_you_have_enough_booleans_t;
    • h4x0r@lemmy.dbzer0.comEnglish
      15·
      2 days ago

      This was gonna be my response to OP so I’ll offer an alternative approach instead:

      typedef enum flags_e : unsigned char {
  F_1 = (1 << 0),
  F_2 = (1 << 1),
  F_3 = (1 << 2),
  F_4 = (1 << 3),
  F_5 = (1 << 4),
  F_6 = (1 << 5),
  F_7 = (1 << 6),
  F_8 = (1 << 7),
} Flags;

int main(void) {
  Flags f = F_1 | F_3 | F_5;
  if (f & F_1 && f & F_3) {
    // do F_1 and F_3 stuff
  }
}
      • anotherandrew@lemmy.mixdown.caEnglish
        1·
        24 hours ago

        Why not if (f & (F_1 | F_3)) {? I use this all the time in embedded code.

        edit: never mind; you’re checking for both flags. I’d probably use (f & (F_1 | F_3)) == (F_1 | F_3) but that’s not much different than what you wrote.

    • xthexder@l.sw0.com
      39·
      2 days ago

      Or just std::bitset<8> for C++. Bit fields are neat though, it can store weird stuff like a 3 bit integer, packed next to booleans