

15·
3 days agoThe same is true of std::endl. std::endl is simply defined as << '\n' << std::flush
; nothing more, nothing less. In all cases where endl gives you a “properly translated” newline, so does \n
.
The same is true of std::endl. std::endl is simply defined as << '\n' << std::flush
; nothing more, nothing less. In all cases where endl gives you a “properly translated” newline, so does \n
.
std::endl provides zero portability benefits. C++ does have a portable newline abstraction, but it is called \n
, not endl.
Yeah, just don’t make any mistakes and you’ll be fine. Come on guys, how hard can it be?